CircleHard
Question
The equation of the normal to the ellipse 
= 1 at the positive end of latus rectum is -
= 1 at the positive end of latus rectum is -Options
A.x + ey + e2a = 0
B.x - ey - e3a = 0
C.x - ey - e2a = 0
D.none of these
Solution
Positive end of latus rectum is (ae, 
)
∴ Equation of normal is
= a2e2
⇒ x - ey - e3a = 0
)∴ Equation of normal is
= a2e2⇒ x - ey - e3a = 0
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