Indefinite IntegrationHard

Question

∫e^{tan^-1x} (1 + x + x²).d(cot^-1 x) is equal to -

Options

A.-e^{tan^-1x} + c

B.e^{tan^-1x} + c

C.-x. e^{tan^-1x} + c

D.x. e^{tan^-1x} + c

Solution

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