Nuclear Physics and RadioactivityHard
Question
A photon of energy 12.09 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of the excited state is
Options
A.4
B.5
C.3
D.2
Solution
Energy difference in hydrogen atom = 13.6 - 
= 12.09 ⇒ n2 ≈ 9 ⇒ n = 3
= 12.09 ⇒ n2 ≈ 9 ⇒ n = 3Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
Let NB be the number of β particles emitted by 1 gram of 24 Na radioactive nuclei (half life = 15 hrs) in 7.5 hours...Which of the following statement is wrong ?...In a sample, ratio of p31 and p32 is 1 : 2. P31 is stable but p32 is radioactive and decays in S32 with half life T. Aft...In hydrogen and hydrogen like atoms, the ratio of difference of energies E2n - En and E2n En varies with its atomic numb...A particular hydrogen like atom has its ground state ground state binding energy 122.4 eV . is It in ground state. Then...