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Indefinite Integration
Hard
Question
Identify the correct expression
Options
A.
x∫ln xdx = x
2
ln | x | -x
2
+ c
B.
x∫ln | x | dx = xe
x
+ c
C.
x∫e
x
dx = e
x
(x-1)+c
D.
+ c
Solution
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Indefinite Integration
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