Definite IntegrationHard
Question
Let u = 
& v = 
then -
& v = then -Options
A.v > u
B.6v = π
C.3u + 2v = 5π/6
D.u + v = π/3
Solution
v = 
Put x =
⇒ dx = 
dt
v = -
v = u
Hence 2u =
dx
=
dx = 
=
2u = π/3
Put x =
⇒ dx = dtv = -
v = u
Hence 2u =
dx=
dx = =
2u = π/3
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