Definite IntegrationHard

Question

Let u = & v = then -

Options

A.v > u
B.6v = π
C.3u + 2v = 5π/6
D.u + v = π/3

Solution

v =
Put x = ⇒ dx = dt
v = -
v = u
Hence 2u = dx
= dx =
=
2u = π/3

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