Definite IntegrationHard

Question

If In = ; n ∈ N, then which of the following statements hold good ?

Options

A.2nIn+1 = 2-n + (2n - 1)In
B.I2 =
C.I2 =
D.I2 =

Solution

In = (1 + x2)-n
In = [(1 + x2)-n .x]01 + n dx
= 2-n + 2n dx
In = 2-n + 2n [In - In+1 ]
2n In+1 = 2-n + (2n - 1) In
Now put n = 1
2I2 = 2-1 + I1 = + dx = + (tan-1 x)10
I2 =

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