Definite IntegrationHard
Question
Let f(x) = 
and g be the inverse of f. Then the value of g′(0) is -
and g be the inverse of f. Then the value of g′(0) is -Options
A.1
B.17
C.
D.none of these
Solution
f(x) = 
[∵ f(2) = 0]
g(f(x)) = x
g′(f(x))f′(x) = 1
g′(0)f′(2) = 2
g′(0) =
= 
⇒ f′(x) =
⇒ f′(2) = 
[∵ f(2) = 0]g(f(x)) = x
g′(f(x))f′(x) = 1
g′(0)f′(2) = 2
g′(0) =
= ⇒ f′(x) =
⇒ f′(2) = Create a free account to view solution
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