Definite IntegrationHard

Question

The value of the definite integral ((x + 1)ex ln x) dx is -

Options

A.e
B.ee + 1
C.ee(e - 1)
D.ee(e - 1) + e

Solution

I = (x + 1)ex ln x dx
= [x ln x + ln x + 1]ex dx
= dx - ex dx
= [x lnxex]e1 - [ex]  = eee - ee + e

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