Definite IntegrationMedium
Question
The value of the definite integral 
((x + 1)ex ln x) dx is -
((x + 1)ex ln x) dx is -Options
A.e
B.ee + 1
C.ee(e - 1)
D.ee(e - 1) + e
Solution
I = 
(x + 1)ex ln x dx
=
[x ln x + ln x + 1]ex dx
=
dx - 
ex dx
= [x lnxex]e1 - [ex] = eee - ee + e
(x + 1)ex ln x dx =
[x ln x + ln x + 1]ex dx=
dx - ex dx= [x lnxex]e1 - [ex] = eee - ee + e
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