Wave OpticsHard
Question
In a YDSE with two identical slits, when the upper slit is covered with a thin, perfectly transparent sheet of mica, the intensity at the centre of screen reduces to 75% of the initial value. Second minima is observed to be above this point and third maxima below it. Which of the following can not be a possible value of phase difference caused by the mica sheet
Options
A.
B.
C.
D.
Solution
I′ = 
(4I) = 3I.
So 4I = I + I + 2I cos
⇒ cos 
= 
⇒ 
= 
but value should lie between 3π & 6π
So it cannot be
For second minima
= 3π
For third maxima = 6π
(4I) = 3I.So 4I = I + I + 2I cos
⇒ cos = ⇒ = but value should lie between 3π & 6π
So it cannot be
For second minima
= 3πFor third maxima
= 6πCreate a free account to view solution
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