PointHard
Question
The pair of straight lines x2 - 4xy + y2 = 0 together with the line x + y + 4√6 = 0 form a triangle which is
Options
A.right angled but not isosscles
B.right isosceles
C.scalene
D.equilateral
Solution
x2 - 4xy + y2 = 0
y2 - 4xy + 4x2 = 3x2
(y - 2x)2 = 3x2
y = (2 ± √3)x
∴ ᐃ formed by L1 = 0, L2 = 0 & L3 = 0 is equilateral
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