Wave OpticsMedium
Question
If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used is : -
Options
A.600 nm
B.525 nm
C.467 nm
D.420 nm
Solution
For minima yn = (2n - 1) 
where n is is the no. of minimum. For maxima yn = 
y5thdark =
; y1*maxima = 
By Equation y5thdark - y1*maxima = 7 × 10-3.
= 7 × 10-3 ⇒ λ = 
∴ λ = 600nm
where n is is the no. of minimum. For maxima yn = y5thdark =
; y1*maxima = By Equation y5thdark - y1*maxima = 7 × 10-3.
= 7 × 10-3 ⇒ λ = ∴ λ = 600nm
Create a free account to view solution
View Solution FreeMore Wave Optics Questions
In a YDSE experiment if a slab whose refractive index can be varied is placed in front of one of the slits then the vari...In a Fraunhofer′s diffraction by a slit, if slit width is a, wave length λ, focal length of lens is f, linear...Two coherent narrow slits emitting light of wave length in the same phase are placed parallel to each other at a small s...In an interference experiment, the spacing between successive maxima or minima is :...The angle of incidence at which reflected light totally polarized for reflection from air to glass (refractive index n),...