Wave OpticsHard
Question
If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used is : -
Options
A.600 nm
B.525 nm
C.467 nm
D.420 nm
Solution
For minima yn = (2n - 1) 
where n is is the no. of minimum. For maxima yn = 
y5thdark =
; y1*maxima = 
By Equation y5thdark - y1*maxima = 7 × 10-3.
= 7 × 10-3 ⇒ λ = 
∴ λ = 600nm
where n is is the no. of minimum. For maxima yn = y5thdark =
; y1*maxima = By Equation y5thdark - y1*maxima = 7 × 10-3.
= 7 × 10-3 ⇒ λ = ∴ λ = 600nm
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