Wave OpticsHard
Question
Two slits separated a distance of 1 m are illuminated with red light of wavelength 6.510-7 m. The interference fringes are observed on a screen placed 1 m from the slits. The distance between the third dark fringe and the fifth fringe is equal to
Options
A.0.65 mm
B.1.625 mm
C.3.25 mm
D.0.975 mm
Solution
Distance between third dark fringe and the fifth bright fringe
= 2.5 β = 2.5
= 2.5 
= 1.625 mm
= 2.5 β = 2.5
= 2.5 = 1.625 mmCreate a free account to view solution
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