PointHard
Question
The line (p + 2q)x + (p - 3q) y = p - q for different values of p and q passes through a fixed point whose cordinates are -
Options
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B.
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D.
Solution
p(x + y - 1) + q(2x - 3y + 1) = 0
x + y - 1 + q/p (2x - 3y + 1) = 0
L1 + λL2 = 0
∴ line always passes through point of intersection of L1 = 0 & L2 = 0.
x + y - 1 + q/p (2x - 3y + 1) = 0
L1 + λL2 = 0
∴ line always passes through point of intersection of L1 = 0 & L2 = 0.
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