PointHard
Question
If one diagonal of a square is along the line x = 2y and one of its vertex is (3, 0) then its sides through this vertex are given by the equations -
Options
A.y - 3x + 9 = 0, x - 3y - 3 = 0
B.y - 3x + 9 = 0, x - 3y - 3 = 0
C.y + 3x - 9 = 0, x + 3y - 3 = 0
D.y - 3x + 9 = 0, x + 3y - 3 = 0
Solution

Let slope of required line is m
tan 45o =
⇒ ± 1 =
equation of lines y = 3(x - 3) & y = -
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