PointHard

Question

If one diagonal of a square is along the line x = 2y and one of its vertex is (3, 0) then its sides through this vertex are given by the equations -

Options

A.y - 3x + 9 = 0, x - 3y - 3 = 0
B.y - 3x + 9 = 0, x - 3y - 3 = 0
C.y + 3x - 9 = 0, x + 3y - 3 = 0
D.y - 3x + 9 = 0, x + 3y - 3 = 0

Solution

       
Let slope of required line is m
tan 45o =
⇒  ± 1 =    ⇒ m = - , 3
equation of lines y = 3(x - 3) & y = -(x - 3)

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