PointHard

Question

Distance of the point (2, 5) from the line 3x + y + 4 = 0 measured parallel to the line 3x - 4y + 8 = 0 is -

Options

A.15/2
B.9/2
C.5
D.none

Solution

   
Let distance be ‘r’.
Co-ordinates of ‘P’ are
(2 + r cos θ, 5 + r sin θ) where tan θ =
which lies on the line 3x + y + 4 = 0
3(2 + r cos q ) + 5 + r sin θ + 4 = 0
r + 1 5 = 0 ⇒ r = - = - 5
but distance can not be negative
∴  r = 5

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