Geometrical OpticsHard
Question
Shown plane mirror is lying in y-z plane . A particle P has velocity
= 5î + 6ĵ at t = 0 & acceleration 
= 2tĵ . Velocity of its image at t = 2s relative to it isOptions
A.10î
B.- 10î
C.20î
D.- 20î
Solution
v1 = 2vM - v0
2 × 0 - (5î + (6 + 2t)ĵ)
v1 = - 5î + 10ĵ ; vI0 = vI - v0
Hence vIo = - 5î + 10ĵ - (5î + 10ĵ)
[at t = 2 sec] = - 10î
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