CircleHard
Question
The locus of the mid-points of the chords of the circle x2 + y2 - 2x - 4y - 11 = 0 which subtend 60o at the centre is -
Options
A.x2 + y2 - 4x - 2y - 7 = 0
B.x2 + y2 + 4x + 2y - 7 = 0
C.x2 + y2 - 2x - 4y - 7 = 0
D.x2 + y2 + 2x + 4y + 7 = 0
Solution
In ᐃ OAB
cos30o =
Squaring both sides, we get the desired locus.
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