Geometrical OpticsMedium
Question
A beam of monochromatic light is incident at i = 50o on one face of an equilateral the angle of emergence is 40o, then the angle of minimum deviation is :
Options
A.30o
B.< 30o
C.≤ 30o
D.≥ 30o
Solution
i = 50o, equilateral prism A = 60o ; e = 40o
Total angle pd deviation
δ = i + e - A = 50 + 40 - 60 ; δ = 30o
Hence δmin < δ ⇒ δmin < 30o
Total angle pd deviation
δ = i + e - A = 50 + 40 - 60 ; δ = 30o
Hence δmin < δ ⇒ δmin < 30o
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