Geometrical OpticsHard
Question
A concave mirror of focal length 20 cm is cut into two parts from the middle and two parts are moved perpendicularly by a distance 1 mm from the previous principle axis AB. the distance between the image formed by the two parts is :
Options
A.2 mm
B.6 mm
C.3 mm
D.4 mm
Solution
For M1 : u = - 10 cm
f = - 20 cm; h0 = - 0.1 cm
v =
⇒ v = 20 cm
m = -
⇒ 
⇒ h1 × 2 × - 0.1 = - 0.2 ; h1 = - 2mm
For m2 =
= 2 ⇒ h1 = 0.2 cm = 2 mm
Distance between two image = 2 mm
f = - 20 cm; h0 = - 0.1 cm
v =
⇒ v = 20 cmm = -
⇒ ⇒ h1 × 2 × - 0.1 = - 0.2 ; h1 = - 2mm
For m2 =
= 2 ⇒ h1 = 0.2 cm = 2 mmDistance between two image = 2 mm
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