Continuity and DifferentiabilityHard
Question
If x
+ y
= 0, then
equals -
Options
A.
B.
C.
D.none of these
Solution
x2(1 + y) = y2(1 + x) ⇒ x2 - y2 + xy(x - y) = 0
⇒ (x - y) (x + y + xy) = 0
Now x ≠ y [does not satisfy the given equation]
∴ x + y + xy = 0 ⇒ y =
∴
⇒ (x - y) (x + y + xy) = 0
Now x ≠ y [does not satisfy the given equation]
∴ x + y + xy = 0 ⇒ y =
∴
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