Continuity and DifferentiabilityHard
Question
If cos-1 
= log a then 
=
= log a then =Options
A.-x/y
B.-y/x
C.y/x
D.x/y
Solution
cos-1
= loga
⇒ 2tan-1
= log a ⇒ tan-1 
⇒ y/x = tan
Now differentiating both sides, we get
= 0 ⇒ 
= loga⇒ 2tan-1
= log a ⇒ tan-1 ⇒ y/x = tan
Now differentiating both sides, we get
= 0 ⇒ Create a free account to view solution
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