Circular MotionHard
Question
A particle moves with deceleration along the circle of radius R so that at moment of time its tangential and normal accelerations are equal in moduli. At the moment t = 0 the speed of the particle equals v0, than the speed of the particle as a function of the distance covered A will be
Options
A.v = v0 e-S/R
B.v = v0 eS/R
C.v = v0 e-R/S
D.v = v0 eR/S
Solution
Given 
⇒ ln
= eS/r
⇒ v0 = veS/r ⇒ v = v0e-S/r
⇒ ln
= eS/r⇒ v0 = veS/r ⇒ v = v0e-S/r
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