Circular MotionHard
Question
A particle moves with deceleration along the circle of radius R so that at moment of time its tangential and normal accelerations are equal in moduli. At the moment t = 0 the speed of the particle equals v0, than the speed of the particle as a function of the distance covered A will be
Options
A.v = v0 e-S/R
B.v = v0 eS/R
C.v = v0 e-R/S
D.v = v0 eR/S
Solution
Given 
⇒ ln
= eS/r
⇒ v0 = veS/r ⇒ v = v0e-S/r
⇒ ln
= eS/r⇒ v0 = veS/r ⇒ v = v0e-S/r
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
A body of mass 5kg is moving in a circle of radius 1 m with an angular velocity of 2rad/ sec.Then the centripetal force ...In case of vertical circular motion of a particle by a thread of length r if the tension in the thread is zero at an ang...A car of mass M is travelling on a horizontal circular path of radius r. At an instant its speed is v and tangential acc...A particle is in motion on the x-axis. The variation of its velocity with position is as shown. The graph is circle and ...A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A plumb bob is suspended ...