LimitsHard
Question
If
[f(x) + g(x)] = 2 and
[f(x) - g(x)] = 1, then
f(x)g(x) -
[f(x) + g(x)] = 2 and[f(x) - g(x)] = 1, thenf(x)g(x) - Options
A.need not exist
B.exist and is 
C.exist and is -
D.exist and is 
Solution
Let
f(x) = L & 
g(x) = M
∵ L + M = 2 & L - M = 1
⇒ L =
& M = 
So
f(x) g(x) = L.M = 
f(x) = L & g(x) = M∵ L + M = 2 & L - M = 1
⇒ L =
& M = So
f(x) g(x) = L.M = Create a free account to view solution
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