Continuity and DifferentiabilityHard
Question
If f (x) = 
then at x = 0, f(x) is -
then at x = 0, f(x) is -Options
A.differentiable
B.not differentiable
C.f′(0+) = -1
D.f′(0-) = 1
Solution
f′(0) = .
= - 1
f′(0+) =
= 1
since f′(0-) ≠ f′(0+)
so f(x) is not differentiable .
= - 1f′(0+) =
= 1since f′(0-) ≠ f′(0+)
so f(x) is not differentiable .
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