KinematicsHard
Question
In the diagram shown, the displacement of particle is given as a function of time The particle A is moving under constant velocity of 9 m/s. The velocity B is moving under variable acceleration From time t = 0 .s to t = 6 s, the average velocity B will be equal to :-
Options
A.2.5 m/s
B.4 m/s
C.9 m/s
D.None
Solution
As given 9 = y / 6 ⇒
Average velocity of particle
B =
= 9m /sCreate a free account to view solution
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