KinematicsHard

Question

A particle A moves along a radius R = 50 cm so that  its radius vector r relative to the  point O (figure) rotates with the constant angular velocity ω = 0.40 rad/s. Then  modulus of the velocity         of the particle and the modulus of its total acceleration will be

Options

A.v = 0.4 m/s, a = 0.4 m/s2
B.v = 0.32 m/s, a = 0.32 m/s2
C.v = 0.32 m/s, a = 0.4 m/s2
D.v = 0.4 m/s, a = 0.32 m/s2

Solution

Angular velocity ω about center  = 2ω
= 2 × 0.40 = 0.30 red /sec
v = ωR
= 0.80 × = 0.40 m/s
a = = 0.32 cm/s2

Create a free account to view solution

View Solution Free
Topic: Kinematics·Practice all Kinematics questions

More Kinematics Questions

A particle is moving eastwards with a velocity of 5 m/s in 10 seconds the velocity changes to 5 m/s northwards. The aver...The motion of a particle along a straight line is described by equation:x = 8 + 12t - t3 where x is in metre and t in se...Relation between velocity and displacement is v = x2. Find acceleration at x = 3m :-...A particle is projected vertically upwards and it reaches the maximum height H in T seconds. The height of the particle ...A projectile thrown with velocity v making θ with vertical gaints maximum height H in the time for which the projec...