KinematicsHard
Question
A particle A moves along a radius R = 50 cm so that its radius vector r relative to the point O (figure) rotates with the constant angular velocity ω = 0.40 rad/s. Then modulus of the velocity of the particle and the modulus of its total acceleration will be
Options
A.v = 0.4 m/s, a = 0.4 m/s2
B.v = 0.32 m/s, a = 0.32 m/s2
C.v = 0.32 m/s, a = 0.4 m/s2
D.v = 0.4 m/s, a = 0.32 m/s2
Solution
Angular velocity ω about center = 2ω
= 2 × 0.40 = 0.30 red /sec
v = ωR
= 0.80 ×
= 0.40 m/s
a =
= 0.32 cm/s2
= 2 × 0.40 = 0.30 red /sec
v = ωR
= 0.80 ×
= 0.40 m/sa =
= 0.32 cm/s2Create a free account to view solution
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