KinematicsHard

Question

A particle A moves along a radius R = 50 cm so that  its radius vector r relative to the  point O (figure) rotates with the constant angular velocity ω = 0.40 rad/s. Then  modulus of the velocity         of the particle and the modulus of its total acceleration will be

Options

A.v = 0.4 m/s, a = 0.4 m/s2
B.v = 0.32 m/s, a = 0.32 m/s2
C.v = 0.32 m/s, a = 0.4 m/s2
D.v = 0.4 m/s, a = 0.32 m/s2

Solution

Angular velocity ω about center  = 2ω
= 2 × 0.40 = 0.30 red /sec
v = ωR
= 0.80 × = 0.40 m/s
a = = 0.32 cm/s2

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