Inverse Trigonometric FunctionHard
Question
The value of sin 
+ cos 
is / are equal to -
+ cos is / are equal to -Options
A.1
B.
C.√2 sin 
D.√2 sin 
Solution
Let 
cot-1 
= θ
expression = sin θ + cos θ = √2 (sin(θ + θ/4))
= √2 sin
= √2 sin
= √2 sin
Also cot 2θ =
so sin θ + cos θ =
cot-1 = θexpression = sin θ + cos θ = √2 (sin(θ + θ/4))
= √2 sin
= √2 sin
= √2 sin
Also cot 2θ =
so sin θ + cos θ =
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