Inverse Trigonometric FunctionHard
Question
(sin-1 x)2 + (sin-1 y)2 + 2(sin-1 x) (sin-1 y) = π2, then x2 + y2 is equal to -
Options
A.1
B.3 / 2
C.2
D.1/2
Solution
(sin-1 x + sin-1 y)2 = π2
sin-1 x + sin-1 y = ± π
⇒ sin-1 x = sin-1 y =
or sin-1 x = sin-1 y = -
⇒ x2 + y2 = 2.
sin-1 x + sin-1 y = ± π
⇒ sin-1 x = sin-1 y =
or sin-1 x = sin-1 y = -
⇒ x2 + y2 = 2.
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