FunctionHard
Question
Range of the function f(x) = cos (K sin x) is [-1 , 1] , then the least positive integral value of K will be -
Options
A.1
B.2
C.3
D.4
Solution
y = cos (K sin x)
= sin x ⇒ - 1 ≤ 
≤ 1
⇒ -K ≤ cos-1 y ≤ K
Now cos-1 y ∈ [0, π]
⇒ K = 4
= sin x ⇒ - 1 ≤ ≤ 1⇒ -K ≤ cos-1 y ≤ K
Now cos-1 y ∈ [0, π]
⇒ K = 4
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