SHMHard
Question
Two waves are represented by the equations y1 = a sin (ωt + kx + 0.57) m and y2 = a sin(ωt + kx)m, where x is in meters and t in sec. The phase difference between them is
Options
A.1.0 radian
B.1.25 radian
C.1.57 radian
D.0.57 radian
Solution
y1 = a sin(ωt + kx + 0.57)m
∴ Phase,φ1 = ωt + k x + 0.57
y2 = a sin (ωt + kx) = a sin
∴ Phase, φ2 = ωt + kx +
Phase difference, ᐃφ = φ2 - φ1
- (ωt + kx +0.57) =
- 0.57
= (1.57 - 0.57) radian = 1 radian
∴ Phase,φ1 = ωt + k x + 0.57
y2 = a sin (ωt + kx) = a sin
∴ Phase, φ2 = ωt + kx +

Phase difference, ᐃφ = φ2 - φ1
- (ωt + kx +0.57) =
- 0.57= (1.57 - 0.57) radian = 1 radian
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