SHMHard
Question
Out of the following function representing motion of a particle which represents SHM
(1) y = sin ωt - cosωt
(2) y = sin3ωt
(3) y = 5 cos
(4) y = 1 + ωt + ω2t2
(1) y = sin ωt - cosωt
(2) y = sin3ωt
(3) y = 5 cos

(4) y = 1 + ωt + ω2t2
Options
A.Only (1)
B.Only (4) does not represent SHM
C.Only (1) and (3)
D.Only (1) and (2)
Solution
y = sinωt - cosωt

It represents a SHM with time period, T =
y = 5 cos
= y = 5 cos
[∵ cos ( - θ = cos θ]
It represents a SHM with time period, T =
y = 1 + ωt + ω2t2
It represented a non-periodic motion. Also it is not physically acceptable as the y → ∞ as t → ∞.

It represents a SHM with time period, T =
y = 5 cos

= y = 5 cos
[∵ cos ( - θ = cos θ] It represents a SHM with time period, T =
y = 1 + ωt + ω2t2
It represented a non-periodic motion. Also it is not physically acceptable as the y → ∞ as t → ∞.
Create a free account to view solution
View Solution FreeMore SHM Questions
In question 35 which of the graph between K.E. and time is correct ?...Which of the graph between acceleration and time is correct ?...A rod of mass M and length L is hinged at its one end and carries a block of mass m at its lower end. A spring of force ...The mass of particle executing S.H.M. is 1 gm. If its periodic time is π seconds, the value of force constant is :...If the amplitude of a simple pendulum is doubled, how many times will the value of its maximum velocity be that of the m...