Application of DerivativeHard
Question
The abscissa of the point on the curve ay2 = x3, the normal at which cuts off equal inter cents from the axes is-
Options
A.1
B.4a/3
C.3
D.4a/9
Solution
The abscissa = ?
Let point (x1, y1) on the curve
ay2 = x3
2ay ×
= 3x2

Normal -
Equal intercept
3x21 = + 2ay1 ..... (1)
point lies on curve ay21 = x31 ..... (2)
solve (1) and (2)
x1 =
Let point (x1, y1) on the curve
ay2 = x3
2ay ×
Normal -
Equal intercept
3x21 = + 2ay1 ..... (1)
point lies on curve ay21 = x31 ..... (2)
solve (1) and (2)
x1 =
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
a, b, c are three distinct real numbers, which are in G.P. and a + b + c = xb, then -...Let f(x) = x3 + ax2 + bx + 5 sin2 x be an increasing function in the set of real numbers R. Then a & b satisfy the condi...The length of the subnormal of the curve y2 = 8ax (a > 0) is -...The surface area of a spherical bubble is increasing at the rate of 2 cm2/s. When the radius of the bubble is 6 cm, then...If the tangents at any point on the curve x4 + y4 = a4 cuts off intercept p and q on the axes, the value of p−4/3 ...