Application of DerivativeHard
Question
The points on the curve y2 = 4a
at which the tangent is parallel to x-axis, lie on-
Options
A.a straight line
B.a parabola
C.a circle
D.a circle
Solution
y2 = 4a 
2y
= 4a 

= 0 = 
= π
x = aπ
y2 = 4a(aπ + a 0)
y2 = 4a2π
y = ± 2a √π
2y
x = aπ
y2 = 4a(aπ + a 0)
y2 = 4a2π
y = ± 2a √π
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