Application of DerivativeMedium
Question
The points on the curve y2 = 4a 
at which the tangent is parallel to x-axis, lie on-
at which the tangent is parallel to x-axis, lie on- Options
A.a straight line
B.a parabola
C.a circle
D.a circle
Solution
y2 = 4a 
2y
= 4a 
= 0 = 
= π
x = aπ
y2 = 4a(aπ + a 0)
y2 = 4a2π
y = ± 2a √π
2y
= 4a = 0 = = π x = aπ
y2 = 4a(aπ + a 0)
y2 = 4a2π
y = ± 2a √π
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
If tangent of the curve x = t2 − 1, y = t2 − t is perpendicular to x- axis, then-...On the interval [0, 1] the function x25(1 - x)75 takes its maximum value at the point...The coordinates of the point of the parabola y2 = 8x , which is at minimum distance from the circlex2 + (y + 6)2 = 1 are...The number of critical points of the function$f(x) = \left\{ \begin{matrix} \left| \frac{sinx}{x} \right|, & x \neq ...The slope of normal to the curve y2 = 4ax at a point (at2, 2at ) is-...