Application of DerivativeMedium
Question
The point where the tangent line to the curve y = e2x at (0, 1) meets x-axis is -
Options
A.(1, 0)
B.(-1, 0)
C.(-1/2, 0)
D.None of these
Solution
y = e2x at (0, 1)
= e2x × 2
= 2
y - 1 = 2 (x - 0)
tangent 2x - y + 1 = 0
meets x axis put y = 0
x = -
point
= e2x × 2= 2y - 1 = 2 (x - 0)
tangent 2x - y + 1 = 0
meets x axis put y = 0
x = -
point
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