MonotonicityHard
Question
The function xx decreases on the interval-
Options
A.(0, e)
B.(0, 1)
C.
D.None of these
Solution
y = xx logy = x logx
= ( 1 + logx) 
= xx (1 + logx) < 0)
x > 0 ( 1+ logx) < 0
x < 1/e ; x ∈
= ( 1 + logx) = xx (1 + logx) < 0)x > 0 ( 1+ logx) < 0
x < 1/e ; x ∈
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