Maxima and MinimaHard

Question

A minimum value of dt is-

Options

A.1
B.2
C.0
D.3

Solution

f(x) = dt
f′(x) = xe-x2 = 0
x = 0
f″(x) = e-x2 (1 - 2x2)
f″ (0) = 1 > 0
Minimum value = f(0) = 0

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