Application of DerivativeMedium
Question
A particle moves along the curve y = x2 + 2x Then the points on the curve are the x and y coordinates of the particle changing at the same rate, are-
Options
A.
B.
C.
D.
Solution
y = x2 + 2x
given
= 1
y = x2 + 2x
= (2x + 2) × 
= 2x + 2 1 = 2x + 2
x = -
; y = -3/4 Points is 
given
= 1y = x2 + 2x
= (2x + 2) × = 2x + 2 1 = 2x + 2x = -
; y = -3/4 Points is Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
Let φ(x) = (f(x))3 - 3(f(x))2 + 4f(x) + 5x + 3 sin x + 4 cos x ∀ x ∈ R, then...Let f and g be increasing and decresing functions respectively from [0, ∞) to [0, ∞) Let h(x) = f (g(x)). If...The value of dy/dx at the point where normal to the curve y = f(x) make equal intercepts with positive direction of coor...Equation of common tangent(s) of x2 - y2 = 12 and xy = 8 is (are) -...The curve y = has...