Application of DerivativeMedium
Question
A particle moves along the curve y = x2 + 2x Then the points on the curve are the x and y coordinates of the particle changing at the same rate, are-
Options
A.
B.
C.
D.
Solution
y = x2 + 2x
given
= 1
y = x2 + 2x
= (2x + 2) × 
= 2x + 2 1 = 2x + 2
x = -
; y = -3/4 Points is 
given
= 1y = x2 + 2x
= (2x + 2) × = 2x + 2 1 = 2x + 2x = -
; y = -3/4 Points is Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
If the tangent at any point on the curve x4 + y4 = a4 cuts off intercept p and q on the axes, the value of p-4/3 + q-4/3...If the line ax + by + c = 0 is a normal to the curve xy = 1, then -...The maximum value of the sum of the A.P. 50, 48, 46, 44, ....... is -...-The equation of normal to the curve y = x3 - 2x2 + 4 at the point x = 2 is-...Let h(x) = f(x) - (f(x))2 + (f(x))3 for every real number x. Then...