DeterminantHard
Question
If fr (x), gr (x), hr (x), r = 1, 2, 3 are polynomials in x such that fr (a) = gr (a) = hr (a), r = 1, 2, 3 and F(x) - 
, then F′ (a) is equal to -
, then F′ (a) is equal to -Options
A.a
B.-a
C.0
D.None of these
Solution
fr(a) = gr(a) = hr(a) r = 1, 2, 3
so f(x) =
f’(x) =
+ 
+ 
so F′ (0) = 0 because two row are identical on putting x = a
so f(x) =
f’(x) =
+ + so F′ (0) = 0 because two row are identical on putting x = a
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