DeterminantHard

Question

If fr (x), gr (x), hr (x), r = 1, 2, 3 are polynomials in x such that fr (a) = gr (a) = hr (a), r = 1, 2, 3 and F(x) - , then F′ (a) is equal to -

Options

A.a
B.-a
C.0
D.None of these

Solution

fr(a) = gr(a) = hr(a)    r = 1, 2, 3
so f(x) =
f’(x) = + +
so F′ (0) = 0 because two row are identical on putting x = a

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