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Continuity and Differentiability
Hard
Question
If x
2
+ y
2
= 1, then -
Options
A.
yy″ - 2(y′)
2
+ 1 = 0
B.
yy″ - 2(y′)
2
+ 1 = 0
C.
yy″ + (y′)
2
- 1 = 0
D.
yy″ + 2(y′)
2
+ 1 = 0
Solution
-
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Continuity and Differentiability
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