Continuity and DifferentiabilityHard

Question

If x2 + y2 = 1, then -

Options

A.yy″ - 2(y′)2 + 1 = 0
B.yy″ - 2(y′)2 + 1 = 0
C.yy″ + (y′)2 - 1 = 0
D.yy″ + 2(y′)2 + 1 = 0

Solution

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