Continuity and DifferentiabilityMedium
Question
Options
A.
B.
C.
D.None of these
Solution
y = cot-1 
Put x = tan θ
y = cot-1
y = cot-1
y = cot-1
y =
- θ =
- tan-1 x

Put x = tan θ
y = cot-1
y = cot-1
y = cot-1
y =
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