Trigonometric EquationHard
Question
The most general values of x for which sin x + cos x = 
{1, a2 - 4a + 6} are given by-
{1, a2 - 4a + 6} are given by-Options
A.2n π
B.2n π + π/2
C.nπ + (-1)n 
D.All of above
Solution
Now a2 - 4a + 6 = (a - 2)2 + 2 > 1
So
{1, a2 - 4a + 6} = 1 ⇒ sin x + cos x = 1
= sin
x +
= nπ + (-1)n 
⇒ x = nπ + (-1)n 
So
{1, a2 - 4a + 6} = 1 ⇒ sin x + cos x = 1= sin
x +
= nπ + (-1)n ⇒ x = nπ + (-1)n Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If y = tan-1 + tan-1 + tan-1 + ..... up to n terms, then is equal to...If tan θ + tan 4θ + tan 7θ = tan θ tan 4θ tan 7θ, then θ =...Find the number of solution of the equation 30 |sin x| = x in 0 ≤ x ≤ 2π...If sin(A + B) = 1 and cos (A - B) = , then find the minimum positive value of A and B is-...The values of θ lying between θ = 0 and θ = π / 2 and satisfing the equation is,...