Trigonometric EquationMedium
Question
The number of values of in the interval [-π, π] satisfying the equation cos θ + sin 2θ = 0 is-
Options
A.1
B.2
C.3
D.4
Solution
cosθ + sin2θ = 0
cosθ + 2sinqcosθ = 0
cosθ (1 + 2sinθ) = 0
⇒ cosθ = 0 or sinθ = - 1/2
θ = -
cosθ = cos
[-π, π]
θ = 2nπ ±
, θ = -
,
cosθ + 2sinqcosθ = 0
cosθ (1 + 2sinθ) = 0
⇒ cosθ = 0 or sinθ = - 1/2
θ = -
cosθ = cos
θ = 2nπ ±
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If 0o < θ < 180o thenthere being n number of 2′s, is equal to-...Let $\frac{\pi}{2} < \theta < \pi$ and $cot\theta = - \frac{1}{2\sqrt{2}}$. Then the value of $sin\left( \frac{15\...General solution of equation 1 + cot θ = cosec θ is-...The solution set of equation cos5x = 1 + sin4x is-...2 ( sin6θ + cos6θ ) - 3(sin4 θ + cos4θ) + 1 is equal to -...