Trigonometric EquationMedium
Question
The general solution of the equation tan2 θ + 2√3 tan θ = 1 is given by -
Options
A.θ = π/2
B.
C.(6n + 1)
D.
Solution
tan2θ + 2 √3 tan θ - 1 = 0
tan θ =
= - √3 ± 2 ⇒ 2 - √3, - 2 - √3
θ = (6n + 1)
tan θ =
= - √3 ± 2 ⇒ 2 - √3, - 2 - √3
θ = (6n + 1)
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