Trigonometric EquationHard
Question
If tan2 θ - (1 + √3) tan θ + √3 = 0, then the general value of θ is :
Options
A.nπ + 
, nπ + 
, nπ + B.nπ - , nπ +
, nπ + C.nπ + , nπ -
, nπ - D.nπ - , nπ -
, nπ - Solution
tan2 θ - tan θ - √3 [tan θ + √3 = 0
tan θ [tan θ -1] - √3 [tan θ -1] = 0
⇒ tan θ = 1, tan θ = √3
θ = nπ +
, θ = nπ + 
tan θ [tan θ -1] - √3 [tan θ -1] = 0
⇒ tan θ = 1, tan θ = √3
θ = nπ +
, θ = nπ + Create a free account to view solution
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