Inverse Trigonometric FunctionHard

Question

The interval in which sin-1x > cos-1x is -

Options

A.
B.
C.[ - 1, 1]
D.

Solution

sin-1x > cos-1x ⇒  sin-1x > - sin-1x
2sin-1x > ⇒  sin-1x >
x > sin ⇒ x > ⇒ x ∈

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