Inverse Trigonometric FunctionMedium
Question
The interval in which sin-1x > cos-1x is -
Options
A.
B.
C.[ - 1, 1]
D.
Solution
sin-1x > cos-1x ⇒ sin-1x >
- sin-1x
2sin-1x >
⇒ sin-1x > 
x > sin
⇒ x >
⇒ x ∈ 
2sin-1x >
x > sin
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