Inverse Trigonometric FunctionHard
Question
The interval in which sin-1x > cos-1x is -
Options
A.
B.
C.[ - 1, 1]
D.
Solution
sin-1x > cos-1x ⇒ sin-1x > 
- sin-1x
2sin-1x >
⇒ sin-1x > 
x > sin
⇒ x > 
⇒ x ∈ 
- sin-1x2sin-1x >
⇒ sin-1x > x > sin
⇒ x > ⇒ x ∈ Create a free account to view solution
View Solution FreeMore Inverse Trigonometric Function Questions
tan =...If sin-1α + sin-1β + sin-1γ = . Then αβ + βγ + γα is -...The value of sin-1 (- √3/2) is -...If cos-1 x - cos-1 y/2 = α, then 4x2 - 4xy cos α + y2 is equal to -...Consider two geometric progressions a1, a2, a3....... an & b1, b2, b3,.......bn with ar = = 2r-1 and another sequence t1...