Inverse Trigonometric FunctionHard

Question

tan-1a + tan-1b, where a > 0, b > 0, ab > 1, is equal to-

Options

A.tan-1
B.tan-1 - π
C.π + tan-1
D.None of these

Solution

-

Create a free account to view solution

View Solution Free
Topic: Inverse Trigonometric Function·Practice all Inverse Trigonometric Function questions

More Inverse Trigonometric Function Questions

cot-1 [ (cos α)1/2] - tan-1 [ (cos α)1/2] = x, then sin x =...sin =...cos [cos-1 (√3 / 2) + sin-1 (1 / √2)] is equal to -...sin-1x + sin-1 + cos-1x + cos-1 =...cos has the value equal to -...