Application of DerivativeHard

Question

If a variable tangent to the curve x2y = c3 makes intercepts a, b on x and y axis respectively, then the value of a2b is -

Options

A.27c3
B.c3
C.c3
D.c3

Solution

Let any point on the curve is
y =
= - 2t3
Equation of tangent is
y - ct2 = 2t3
For x intercept
0 - ct2 = - 2t3 ⇒   
a =
For y intercept
b - ct2 = - 2t3
⇒ b - ct2 = 2t2c  ⇒ b = 3ct2
Now a2b = × 3ct2 =

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