MonotonicityHard
Question
Number of solution of the equation 3tan x + x3= 2 in
is
isOptions
A.0
B.1
C.2
D.3
Solution
f(x) = 3tan x + x3 - 2, f′(x) = 3(sec2 x + x2) > 0
⇒ f (x) is increasing in ∀ x ∈ (0, π/4)
f(0) < 0 & f
> 0
⇒ f(x) = 0 has exactly one root in
f(x) = 3tan x + x3 - 2, f′(x) = 3(sec2 x + x2) > 0
⇒ f (x) is increasing in ∀ x ∈ (0, π/4)
f(0) < 0 & f > 0
⇒ f(x) = 0 has exactly one root in
⇒ f (x) is increasing in ∀ x ∈ (0, π/4)
f(0) < 0 & f
> 0⇒ f(x) = 0 has exactly one root in
f(x) = 3tan x + x3 - 2, f′(x) = 3(sec2 x + x2) > 0⇒ f (x) is increasing in ∀ x ∈ (0, π/4)
f(0) < 0 & f
> 0⇒ f(x) = 0 has exactly one root in
Create a free account to view solution
View Solution FreeMore Monotonicity Questions
Function is -...Function f(x) = log x is monotonic increasing when-...Function f(x) = kx + 3 sin x is decreasing if-...If a < 0 then function (eax + e−ax) is monotonic decreasing when...Consider f(x) = l 1 - x l , 1 ≤ x ≤ 2 and g(x) = f(x) + b sin π/2 x, 1 ≤ x ≤ 2 then which o...