Area under the curveHard
Question
Consider the following regions in the plane :
R1 = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1} and R2 = {(x, y) : x2 + y2 ≤ 4/3}
The area of the region R1 ∩ R2 can be expressed as
, where a and b are integers, then -
R1 = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1} and R2 = {(x, y) : x2 + y2 ≤ 4/3}
The area of the region R1 ∩ R2 can be expressed as
Options
A.a = 3
B.a = 1
C.b = 1
D.b = 3
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