Quadratic EquationHard

Question

The number of values of k, for which the system of equations :
(k + 1)x + 8y = 4k
kx + (k + 3)y = 3k - 1
has no solution, is :

Options

A.infinite
B.1
C.2
D.3

Solution

       
     (1) = (2)
       ⇒k2 - 4k + 3 = 0
      k = 1, 3
      for k = 1,      (2) = (3)
      for k = 3,       (2) ≠ (3)
      k = 3

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